Test: Difference between revisions

Latest revision as of 15:07, 19 November 2024

[math]\displaystyle{ E=mc^2 }[/math]

[math]\displaystyle{ 2 + 2 = 4 }[/math]

[math]\displaystyle{ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} }[/math]

[math]\displaystyle{ a^2 + b^2 = c^2 }[/math]

[math]\displaystyle{ e^{i\pi} + 1 = 0 }[/math]

[math]\displaystyle{ \int_0^\infty e^{-x^2} dx = \frac{\sqrt{\pi}}{2} }[/math]

[math]\displaystyle{ \sum_{n=1}^{\infty} \frac{1}{n^2} = \frac{\pi^2}{6} }[/math]

[math]\displaystyle{ \begin{pmatrix} 1 & 2 \\ 3 & 4 \end{pmatrix} }[/math]

[math]\displaystyle{ \frac{d}{dx} \left( x^2 \right) = 2x }[/math]

[math]\displaystyle{ (x + y)^n = \sum_{k=0}^n \binom{n}{k} x^{n-k} y^k }[/math]

[math]\displaystyle{ \lim_{x \to 0} \frac{\sin x}{x} = 1 }[/math]

@@ Line 1: / Line 1: @@
-<pre>
+<math>E=mc^2</math>
-王天霸		你好	你好		你不好	无知
-什么		矢	不知		明明	油费
+<math>2 + 2 = 4</math>
-</pre>
+<math>x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}</math>
-有 302 不
+<math>a^2 + b^2 = c^2</math>
-有但是快得如流星
+<math>e^{i\pi} + 1 = 0</math>
-<math>E=mc^2</math>
+<math>\int_0^\infty e^{-x^2} dx = \frac{\sqrt{\pi}}{2}</math>
-<math> 2 + 2 = 4 </math>
+<math>\sum_{n=1}^{\infty} \frac{1}{n^2} = \frac{\pi^2}{6}</math>
-x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
+<math>\begin{pmatrix}
-a^2 + b^2 = c^2
-e^{i\pi} + 1 = 0
-\int_0^\infty e^{-x^2} dx = \frac{\sqrt{\pi}}{2}
-\sum_{n=1}^{\infty} \frac{1}{n^2} = \frac{\pi^2}{6}
-\begin{pmatrix}
 & 2 \\
 & 4
-\end{pmatrix}
+\end{pmatrix}</math>
-\frac{d}{dx} \left( x^2 \right) = 2x
-(x + y)^n = \sum_{k=0}^n \binom{n}{k} x^{n-k} y^k
+<math>\frac{d}{dx} \left( x^2 \right) = 2x</math>
-\lim_{x \to 0} \frac{\sin x}{x} = 1
+<math>(x + y)^n = \sum_{k=0}^n \binom{n}{k} x^{n-k} y^k</math>
+<math>\lim_{x \to 0} \frac{\sin x}{x} = 1</math>