Test math: Difference between revisions
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Created page with "<math>E=mc^2</math> <math>2 + 2 = 4</math> <math>x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}</math> <math>a^2 + b^2 = c^2</math> <math>e^{i\pi} + 1 = 0</math> <math>\int_0^\infty e^{-x^2} dx = \frac{\sqrt{\pi}}{2}</math> <math>\sum_{n=1}^{\infty} \frac{1}{n^2} = \frac{\pi^2}{6}</math> <math>\begin{pmatrix} 1 & 2 \\ 3 & 4 \end{pmatrix}</math> <math>\frac{d}{dx} \left( x^2 \right) = 2x</math> <math>(x + y)^n = \sum_{k=0}^n \binom{n}{k} x^{n-k} y^k</math> <math>\lim_{x..." |
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Latest revision as of 17:04, 16 January 2025
[math]\displaystyle{ E=mc^2 }[/math]
[math]\displaystyle{ 2 + 2 = 4 }[/math]
[math]\displaystyle{ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} }[/math]
[math]\displaystyle{ a^2 + b^2 = c^2 }[/math]
[math]\displaystyle{ e^{i\pi} + 1 = 0 }[/math]
[math]\displaystyle{ \int_0^\infty e^{-x^2} dx = \frac{\sqrt{\pi}}{2} }[/math]
[math]\displaystyle{ \sum_{n=1}^{\infty} \frac{1}{n^2} = \frac{\pi^2}{6} }[/math]
[math]\displaystyle{ \begin{pmatrix} 1 & 2 \\ 3 & 4 \end{pmatrix} }[/math]
[math]\displaystyle{ \frac{d}{dx} \left( x^2 \right) = 2x }[/math]
[math]\displaystyle{ (x + y)^n = \sum_{k=0}^n \binom{n}{k} x^{n-k} y^k }[/math]
[math]\displaystyle{ \lim_{x \to 0} \frac{\sin x}{x} = 1 }[/math]
